4(z+12)=80

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Solution for 4(z+12)=80 equation:



4(z+12)=80
We move all terms to the left:
4(z+12)-(80)=0
We multiply parentheses
4z+48-80=0
We add all the numbers together, and all the variables
4z-32=0
We move all terms containing z to the left, all other terms to the right
4z=32
z=32/4
z=8

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