4(z+2)=2(4-z)+42

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Solution for 4(z+2)=2(4-z)+42 equation:


Simplifying
4(z + 2) = 2(4 + -1z) + 42

Reorder the terms:
4(2 + z) = 2(4 + -1z) + 42
(2 * 4 + z * 4) = 2(4 + -1z) + 42
(8 + 4z) = 2(4 + -1z) + 42
8 + 4z = (4 * 2 + -1z * 2) + 42
8 + 4z = (8 + -2z) + 42

Reorder the terms:
8 + 4z = 8 + 42 + -2z

Combine like terms: 8 + 42 = 50
8 + 4z = 50 + -2z

Solving
8 + 4z = 50 + -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
8 + 4z + 2z = 50 + -2z + 2z

Combine like terms: 4z + 2z = 6z
8 + 6z = 50 + -2z + 2z

Combine like terms: -2z + 2z = 0
8 + 6z = 50 + 0
8 + 6z = 50

Add '-8' to each side of the equation.
8 + -8 + 6z = 50 + -8

Combine like terms: 8 + -8 = 0
0 + 6z = 50 + -8
6z = 50 + -8

Combine like terms: 50 + -8 = 42
6z = 42

Divide each side by '6'.
z = 7

Simplifying
z = 7

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