4(z+2)=3(z+1)

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Solution for 4(z+2)=3(z+1) equation: 



4(z+2)=3(z+1)

We move all terms to the left:

4(z+2)-(3(z+1))=0

We multiply parentheses

4z-(3(z+1))+8=0



We calculate terms in parentheses: -(3(z+1)), so:

3(z+1)

We multiply parentheses

3z+3

Back to the equation:

-(3z+3)



We get rid of parentheses

4z-3z-3+8=0

We add all the numbers together, and all the variables

z+5=0

We move all terms containing z to the left, all other terms to the right

z=-5

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