4(z+2)=3(z-4)+z

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Solution for 4(z+2)=3(z-4)+z equation: 


Simplifying
4(z + 2) = 3(z + -4) + z

Reorder the terms:
4(2 + z) = 3(z + -4) + z
(2 * 4 + z * 4) = 3(z + -4) + z
(8 + 4z) = 3(z + -4) + z

Reorder the terms:
8 + 4z = 3(-4 + z) + z
8 + 4z = (-4 * 3 + z * 3) + z
8 + 4z = (-12 + 3z) + z

Combine like terms: 3z + z = 4z
8 + 4z = -12 + 4z

Add '-4z' to each side of the equation.
8 + 4z + -4z = -12 + 4z + -4z

Combine like terms: 4z + -4z = 0
8 + 0 = -12 + 4z + -4z
8 = -12 + 4z + -4z

Combine like terms: 4z + -4z = 0
8 = -12 + 0
8 = -12

Solving
8 = -12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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