4(z+3)-4=28(.5z+1)

Solution for 4(z+3)-4=28(.5z+1) equation:

4(z+3)-4=28(.5z+1)

We move all terms to the left:

4(z+3)-4-(28(.5z+1))=0

We multiply parentheses

4z-(28(.5z+1))+12-4=0


We calculate terms in parentheses: -(28(.5z+1)), so:

28(.5z+1)

We multiply parentheses

28z+28

Back to the equation:

-(28z+28)


We add all the numbers together, and all the variables

4z-(28z+28)+8=0

We get rid of parentheses

4z-28z-28+8=0

We add all the numbers together, and all the variables

-24z-20=0

We move all terms containing z to the left, all other terms to the right

-24z=20

z=20/-24

z=-5/6