4(z+3)-4=8(1/2z+1)

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Solution for 4(z+3)-4=8(1/2z+1) equation: 



4(z+3)-4=8(1/2z+1)

We move all terms to the left:

4(z+3)-4-(8(1/2z+1))=0



Domain of the equation: 2z+1))!=0

z∈R



We multiply parentheses

4z-(8(1/2z+1))+12-4=0

We multiply all the terms by the denominator


4z*2z+12*2z+1))-4*2z+1))+1))-(8(1=0

Wy multiply elements

8z^2+24z+1))-4*2z+1))+1))-(8(1=0

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