4(z+3)=-3(z-4)

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Solution for 4(z+3)=-3(z-4) equation:


Simplifying
4(z + 3) = -3(z + -4)

Reorder the terms:
4(3 + z) = -3(z + -4)
(3 * 4 + z * 4) = -3(z + -4)
(12 + 4z) = -3(z + -4)

Reorder the terms:
12 + 4z = -3(-4 + z)
12 + 4z = (-4 * -3 + z * -3)
12 + 4z = (12 + -3z)

Add '-12' to each side of the equation.
12 + -12 + 4z = 12 + -12 + -3z

Combine like terms: 12 + -12 = 0
0 + 4z = 12 + -12 + -3z
4z = 12 + -12 + -3z

Combine like terms: 12 + -12 = 0
4z = 0 + -3z
4z = -3z

Solving
4z = -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
4z + 3z = -3z + 3z

Combine like terms: 4z + 3z = 7z
7z = -3z + 3z

Combine like terms: -3z + 3z = 0
7z = 0

Divide each side by '7'.
z = 0

Simplifying
z = 0

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