4(z+3)=8(4+z)

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Solution for 4(z+3)=8(4+z) equation: 



4(z+3)=8(4+z)

We move all terms to the left:

4(z+3)-(8(4+z))=0

We add all the numbers together, and all the variables

4(z+3)-(8(z+4))=0

We multiply parentheses

4z-(8(z+4))+12=0



We calculate terms in parentheses: -(8(z+4)), so:

8(z+4)

We multiply parentheses

8z+32

Back to the equation:

-(8z+32)



We get rid of parentheses

4z-8z-32+12=0

We add all the numbers together, and all the variables

-4z-20=0

We move all terms containing z to the left, all other terms to the right

-4z=20

z=20/-4

z=-5

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