4(z+5)=48

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Solution for 4(z+5)=48 equation:



4(z+5)=48
We move all terms to the left:
4(z+5)-(48)=0
We multiply parentheses
4z+20-48=0
We add all the numbers together, and all the variables
4z-28=0
We move all terms containing z to the left, all other terms to the right
4z=28
z=28/4
z=7

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