4(z+5)=48

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Solution for 4(z+5)=48 equation: 



4(z+5)=48

We move all terms to the left:

4(z+5)-(48)=0

We multiply parentheses

4z+20-48=0

We add all the numbers together, and all the variables

4z-28=0

We move all terms containing z to the left, all other terms to the right

4z=28

z=28/4

z=7

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