4(z+6)=3(2z)

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Solution for 4(z+6)=3(2z) equation: 



4(z+6)=3(2z)

We move all terms to the left:

4(z+6)-(3(2z))=0

determiningTheFunctionDomain
4(z+6)-32z=0

We add all the numbers together, and all the variables

-32z+4(z+6)=0

We multiply parentheses

-32z+4z+24=0

We add all the numbers together, and all the variables

-28z+24=0

We move all terms containing z to the left, all other terms to the right

-28z=-24

z=-24/-28

z=6/7

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