4(z+7)+2z=1

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Solution for 4(z+7)+2z=1 equation: 



4(z+7)+2z=1

We move all terms to the left:

4(z+7)+2z-(1)=0

We add all the numbers together, and all the variables

2z+4(z+7)-1=0

We multiply parentheses

2z+4z+28-1=0

We add all the numbers together, and all the variables

6z+27=0

We move all terms containing z to the left, all other terms to the right

6z=-27

z=-27/6

z=-4+1/2

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