4(z+z+2)-(z+4)=60

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Solution for 4(z+z+2)-(z+4)=60 equation:


Simplifying
4(z + z + 2) + -1(z + 4) = 60

Reorder the terms:
4(2 + z + z) + -1(z + 4) = 60

Combine like terms: z + z = 2z
4(2 + 2z) + -1(z + 4) = 60
(2 * 4 + 2z * 4) + -1(z + 4) = 60
(8 + 8z) + -1(z + 4) = 60

Reorder the terms:
8 + 8z + -1(4 + z) = 60
8 + 8z + (4 * -1 + z * -1) = 60
8 + 8z + (-4 + -1z) = 60

Reorder the terms:
8 + -4 + 8z + -1z = 60

Combine like terms: 8 + -4 = 4
4 + 8z + -1z = 60

Combine like terms: 8z + -1z = 7z
4 + 7z = 60

Solving
4 + 7z = 60

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 7z = 60 + -4

Combine like terms: 4 + -4 = 0
0 + 7z = 60 + -4
7z = 60 + -4

Combine like terms: 60 + -4 = 56
7z = 56

Divide each side by '7'.
z = 8

Simplifying
z = 8

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