4(z-1)+3(2z+2)=36

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Solution for 4(z-1)+3(2z+2)=36 equation: 



4(z-1)+3(2z+2)=36

We move all terms to the left:

4(z-1)+3(2z+2)-(36)=0

We multiply parentheses

4z+6z-4+6-36=0

We add all the numbers together, and all the variables

10z-34=0

We move all terms containing z to the left, all other terms to the right

10z=34

z=34/10

z=3+2/5

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