4(z-1)+3(2z+2)=36

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Solution for 4(z-1)+3(2z+2)=36 equation:



4(z-1)+3(2z+2)=36
We move all terms to the left:
4(z-1)+3(2z+2)-(36)=0
We multiply parentheses
4z+6z-4+6-36=0
We add all the numbers together, and all the variables
10z-34=0
We move all terms containing z to the left, all other terms to the right
10z=34
z=34/10
z=3+2/5

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