4(z-1)+3=-20-(z-4)

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Solution for 4(z-1)+3=-20-(z-4) equation: 



4(z-1)+3=-20-(z-4)

We move all terms to the left:

4(z-1)+3-(-20-(z-4))=0

We multiply parentheses

4z-(-20-(z-4))-4+3=0



We calculate terms in parentheses: -(-20-(z-4)), so:

-20-(z-4)

determiningTheFunctionDomain
-(z-4)-20

We get rid of parentheses

-z+4-20

We add all the numbers together, and all the variables

-1z-16

Back to the equation:

-(-1z-16)



We add all the numbers together, and all the variables

4z-(-1z-16)-1=0

We get rid of parentheses

4z+1z+16-1=0

We add all the numbers together, and all the variables

5z+15=0

We move all terms containing z to the left, all other terms to the right

5z=-15

z=-15/5

z=-3

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