4(z-1)=2(z+1)

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Solution for 4(z-1)=2(z+1) equation:


Simplifying
4(z + -1) = 2(z + 1)

Reorder the terms:
4(-1 + z) = 2(z + 1)
(-1 * 4 + z * 4) = 2(z + 1)
(-4 + 4z) = 2(z + 1)

Reorder the terms:
-4 + 4z = 2(1 + z)
-4 + 4z = (1 * 2 + z * 2)
-4 + 4z = (2 + 2z)

Solving
-4 + 4z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-4 + 4z + -2z = 2 + 2z + -2z

Combine like terms: 4z + -2z = 2z
-4 + 2z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-4 + 2z = 2 + 0
-4 + 2z = 2

Add '4' to each side of the equation.
-4 + 4 + 2z = 2 + 4

Combine like terms: -4 + 4 = 0
0 + 2z = 2 + 4
2z = 2 + 4

Combine like terms: 2 + 4 = 6
2z = 6

Divide each side by '2'.
z = 3

Simplifying
z = 3

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