4(z-1)=2(z+2)

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Solution for 4(z-1)=2(z+2) equation: 



4(z-1)=2(z+2)

We move all terms to the left:

4(z-1)-(2(z+2))=0

We multiply parentheses

4z-(2(z+2))-4=0



We calculate terms in parentheses: -(2(z+2)), so:

2(z+2)

We multiply parentheses

2z+4

Back to the equation:

-(2z+4)



We get rid of parentheses

4z-2z-4-4=0

We add all the numbers together, and all the variables

2z-8=0

We move all terms containing z to the left, all other terms to the right

2z=8

z=8/2

z=4

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