4(z-1)=29

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Solution for 4(z-1)=29 equation: 



4(z-1)=29

We move all terms to the left:

4(z-1)-(29)=0

We multiply parentheses

4z-4-29=0

We add all the numbers together, and all the variables

4z-33=0

We move all terms containing z to the left, all other terms to the right

4z=33

z=33/4

z=8+1/4

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