4(z-15)=2(z+10)

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Solution for 4(z-15)=2(z+10) equation: 



4(z-15)=2(z+10)

We move all terms to the left:

4(z-15)-(2(z+10))=0

We multiply parentheses

4z-(2(z+10))-60=0



We calculate terms in parentheses: -(2(z+10)), so:

2(z+10)

We multiply parentheses

2z+20

Back to the equation:

-(2z+20)



We get rid of parentheses

4z-2z-20-60=0

We add all the numbers together, and all the variables

2z-80=0

We move all terms containing z to the left, all other terms to the right

2z=80

z=80/2

z=40

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