4(z-2)+3(2-z)=8(1-z)

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Solution for 4(z-2)+3(2-z)=8(1-z) equation: 



4(z-2)+3(2-z)=8(1-z)

We move all terms to the left:

4(z-2)+3(2-z)-(8(1-z))=0

We add all the numbers together, and all the variables

4(z-2)+3(-1z+2)-(8(-1z+1))=0

We multiply parentheses

4z-3z-(8(-1z+1))-8+6=0



We calculate terms in parentheses: -(8(-1z+1)), so:

8(-1z+1)

We multiply parentheses

-8z+8

Back to the equation:

-(-8z+8)



We add all the numbers together, and all the variables

z-(-8z+8)-2=0

We get rid of parentheses

z+8z-8-2=0

We add all the numbers together, and all the variables

9z-10=0

We move all terms containing z to the left, all other terms to the right

9z=10

z=10/9

z=1+1/9

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