4(z-2)+3(4+4)=-12

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Solution for 4(z-2)+3(4+4)=-12 equation: 


Simplifying
4(z + -2) + 3(4 + 4) = -12

Reorder the terms:
4(-2 + z) + 3(4 + 4) = -12
(-2 * 4 + z * 4) + 3(4 + 4) = -12
(-8 + 4z) + 3(4 + 4) = -12

Combine like terms: 4 + 4 = 8
-8 + 4z + 3(8) = -12

Multiply 3 * 8
-8 + 4z + 24 = -12

Reorder the terms:
-8 + 24 + 4z = -12

Combine like terms: -8 + 24 = 16
16 + 4z = -12

Solving
16 + 4z = -12

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 4z = -12 + -16

Combine like terms: 16 + -16 = 0
0 + 4z = -12 + -16
4z = -12 + -16

Combine like terms: -12 + -16 = -28
4z = -28

Divide each side by '4'.
z = -7

Simplifying
z = -7

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