4(z-2)+z=-6

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Solution for 4(z-2)+z=-6 equation: 



4(z-2)+z=-6

We move all terms to the left:

4(z-2)+z-(-6)=0

We add all the numbers together, and all the variables

z+4(z-2)+6=0

We multiply parentheses

z+4z-8+6=0

We add all the numbers together, and all the variables

5z-2=0

We move all terms containing z to the left, all other terms to the right

5z=2

z=2/5

z=2/5

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