4(z-2)=13-3z

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Solution for 4(z-2)=13-3z equation:



4(z-2)=13-3z
We move all terms to the left:
4(z-2)-(13-3z)=0
We add all the numbers together, and all the variables
4(z-2)-(-3z+13)=0
We multiply parentheses
4z-(-3z+13)-8=0
We get rid of parentheses
4z+3z-13-8=0
We add all the numbers together, and all the variables
7z-21=0
We move all terms containing z to the left, all other terms to the right
7z=21
z=21/7
z=3

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