4(z-2)=4z-8

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Solution for 4(z-2)=4z-8 equation:


Simplifying
4(z + -2) = 4z + -8

Reorder the terms:
4(-2 + z) = 4z + -8
(-2 * 4 + z * 4) = 4z + -8
(-8 + 4z) = 4z + -8

Reorder the terms:
-8 + 4z = -8 + 4z

Add '8' to each side of the equation.
-8 + 8 + 4z = -8 + 8 + 4z

Combine like terms: -8 + 8 = 0
0 + 4z = -8 + 8 + 4z
4z = -8 + 8 + 4z

Combine like terms: -8 + 8 = 0
4z = 0 + 4z
4z = 4z

Add '-4z' to each side of the equation.
4z + -4z = 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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