4(z-3)+2z=3(2z-5)

Solution for 4(z-3)+2z=3(2z-5) equation:

Simplifying
4(z + -3) + 2z = 3(2z + -5)

Reorder the terms:
4(-3 + z) + 2z = 3(2z + -5)
(-3 * 4 + z * 4) + 2z = 3(2z + -5)
(-12 + 4z) + 2z = 3(2z + -5)

Combine like terms: 4z + 2z = 6z
-12 + 6z = 3(2z + -5)

Reorder the terms:
-12 + 6z = 3(-5 + 2z)
-12 + 6z = (-5 * 3 + 2z * 3)
-12 + 6z = (-15 + 6z)

Add '-6z' to each side of the equation.
-12 + 6z + -6z = -15 + 6z + -6z

Combine like terms: 6z + -6z = 0
-12 + 0 = -15 + 6z + -6z
-12 = -15 + 6z + -6z

Combine like terms: 6z + -6z = 0
-12 = -15 + 0
-12 = -15

Solving
-12 = -15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.