4(z-3)=2z+6

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Solution for 4(z-3)=2z+6 equation: 



4(z-3)=2z+6

We move all terms to the left:

4(z-3)-(2z+6)=0

We multiply parentheses

4z-(2z+6)-12=0

We get rid of parentheses

4z-2z-6-12=0

We add all the numbers together, and all the variables

2z-18=0

We move all terms containing z to the left, all other terms to the right

2z=18

z=18/2

z=9

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