4(z-3)=2z/9+22

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Solution for 4(z-3)=2z/9+22 equation: 



4(z-3)=2z/9+22

We move all terms to the left:

4(z-3)-(2z/9+22)=0

We multiply parentheses

4z-(2z/9+22)-12=0

We get rid of parentheses

4z-2z/9-22-12=0

We multiply all the terms by the denominator


4z*9-2z-22*9-12*9=0

We add all the numbers together, and all the variables

-2z+4z*9-306=0

Wy multiply elements

-2z+36z-306=0

We add all the numbers together, and all the variables

34z-306=0

We move all terms containing z to the left, all other terms to the right

34z=306

z=306/34

z=9

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