4(z-3)=8(4-z)

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Solution for 4(z-3)=8(4-z) equation:



4(z-3)=8(4-z)
We move all terms to the left:
4(z-3)-(8(4-z))=0
We add all the numbers together, and all the variables
4(z-3)-(8(-1z+4))=0
We multiply parentheses
4z-(8(-1z+4))-12=0
We calculate terms in parentheses: -(8(-1z+4)), so:
8(-1z+4)
We multiply parentheses
-8z+32
Back to the equation:
-(-8z+32)
We get rid of parentheses
4z+8z-32-12=0
We add all the numbers together, and all the variables
12z-44=0
We move all terms containing z to the left, all other terms to the right
12z=44
z=44/12
z=3+2/3

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