4(z-4)=-48

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Solution for 4(z-4)=-48 equation: 



4(z-4)=-48

We move all terms to the left:

4(z-4)-(-48)=0

We add all the numbers together, and all the variables

4(z-4)+48=0

We multiply parentheses

4z-16+48=0

We add all the numbers together, and all the variables

4z+32=0

We move all terms containing z to the left, all other terms to the right

4z=-32

z=-32/4

z=-8

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