4(z-4)=3(z+2)

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Solution for 4(z-4)=3(z+2) equation: 



4(z-4)=3(z+2)

We move all terms to the left:

4(z-4)-(3(z+2))=0

We multiply parentheses

4z-(3(z+2))-16=0



We calculate terms in parentheses: -(3(z+2)), so:

3(z+2)

We multiply parentheses

3z+6

Back to the equation:

-(3z+6)



We get rid of parentheses

4z-3z-6-16=0

We add all the numbers together, and all the variables

z-22=0

We move all terms containing z to the left, all other terms to the right

z=22

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