4(z-4)=3(z+2)

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Solution for 4(z-4)=3(z+2) equation:



4(z-4)=3(z+2)
We move all terms to the left:
4(z-4)-(3(z+2))=0
We multiply parentheses
4z-(3(z+2))-16=0
We calculate terms in parentheses: -(3(z+2)), so:
3(z+2)
We multiply parentheses
3z+6
Back to the equation:
-(3z+6)
We get rid of parentheses
4z-3z-6-16=0
We add all the numbers together, and all the variables
z-22=0
We move all terms containing z to the left, all other terms to the right
z=22

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