4(z-5)+2=4z-1

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Solution for 4(z-5)+2=4z-1 equation: 



4(z-5)+2=4z-1

We move all terms to the left:

4(z-5)+2-(4z-1)=0

We multiply parentheses

4z-(4z-1)-20+2=0

We get rid of parentheses

4z-4z+1-20+2=0

We add all the numbers together, and all the variables

-17!=0

There is no solution for this equation

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