4(z-5)+2=4z-18

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Solution for 4(z-5)+2=4z-18 equation:


Simplifying
4(z + -5) + 2 = 4z + -18

Reorder the terms:
4(-5 + z) + 2 = 4z + -18
(-5 * 4 + z * 4) + 2 = 4z + -18
(-20 + 4z) + 2 = 4z + -18

Reorder the terms:
-20 + 2 + 4z = 4z + -18

Combine like terms: -20 + 2 = -18
-18 + 4z = 4z + -18

Reorder the terms:
-18 + 4z = -18 + 4z

Add '18' to each side of the equation.
-18 + 18 + 4z = -18 + 18 + 4z

Combine like terms: -18 + 18 = 0
0 + 4z = -18 + 18 + 4z
4z = -18 + 18 + 4z

Combine like terms: -18 + 18 = 0
4z = 0 + 4z
4z = 4z

Add '-4z' to each side of the equation.
4z + -4z = 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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