4(z-6)+2z=6(z+4)-48

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Solution for 4(z-6)+2z=6(z+4)-48 equation:


Simplifying
4(z + -6) + 2z = 6(z + 4) + -48

Reorder the terms:
4(-6 + z) + 2z = 6(z + 4) + -48
(-6 * 4 + z * 4) + 2z = 6(z + 4) + -48
(-24 + 4z) + 2z = 6(z + 4) + -48

Combine like terms: 4z + 2z = 6z
-24 + 6z = 6(z + 4) + -48

Reorder the terms:
-24 + 6z = 6(4 + z) + -48
-24 + 6z = (4 * 6 + z * 6) + -48
-24 + 6z = (24 + 6z) + -48

Reorder the terms:
-24 + 6z = 24 + -48 + 6z

Combine like terms: 24 + -48 = -24
-24 + 6z = -24 + 6z

Add '24' to each side of the equation.
-24 + 24 + 6z = -24 + 24 + 6z

Combine like terms: -24 + 24 = 0
0 + 6z = -24 + 24 + 6z
6z = -24 + 24 + 6z

Combine like terms: -24 + 24 = 0
6z = 0 + 6z
6z = 6z

Add '-6z' to each side of the equation.
6z + -6z = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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