4(z-62)=80

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Solution for 4(z-62)=80 equation: 



4(z-62)=80

We move all terms to the left:

4(z-62)-(80)=0

We multiply parentheses

4z-248-80=0

We add all the numbers together, and all the variables

4z-328=0

We move all terms containing z to the left, all other terms to the right

4z=328

z=328/4

z=82

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