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4*(16x^2/4)=
We move all terms to the left:
4*(16x^2/4)-()=0
We add all the numbers together, and all the variables
4*(16x^2/4)=0
We multiply parentheses
64x^2=0
a = 64; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·64·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{128}=0$
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