4*(n+(-5))-2=26-2(-n)

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Solution for 4*(n+(-5))-2=26-2(-n) equation: 



4(n+(-5))-2=26-2(-n)

We move all terms to the left:

4(n+(-5))-2-(26-2(-n))=0

We add all the numbers together, and all the variables

4(n+(-5))-(26-2(-1n))-2=0



We calculate terms in parentheses: -(26-2(-1n)), so:

26-2(-1n)

determiningTheFunctionDomain
-2(-1n)+26

We multiply parentheses

2n+26

Back to the equation:

-(2n+26)



We get rid of parentheses

4(n+(-5))-2n-26-2=0

We add all the numbers together, and all the variables

-2n+4(n+(-5))-28=0

We move all terms containing n to the left, all other terms to the right

-2n+4(n+(-5))=28

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