4*(x+2)+1/2-(3-x)=7/2+x

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Solution for 4*(x+2)+1/2-(3-x)=7/2+x equation: 



4(x+2)+1/2-(3-x)=7/2+x

We move all terms to the left:

4(x+2)+1/2-(3-x)-(7/2+x)=0



Domain of the equation: 2+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-2

x!=-2/1

x!=-2

x∈R



We add all the numbers together, and all the variables

4(x+2)-(-1x+3)-(+x+7/2)+1/2=0

We multiply parentheses

4x-(-1x+3)-(+x+7/2)+8+1/2=0

We get rid of parentheses

4x+1x-x-3+8-7/2+1/2=0

We multiply all the terms by the denominator


4x*2+1x*2-x*2-7+1-3*2+8*2=0

We add all the numbers together, and all the variables

4x*2+1x*2-x*2+4=0

Wy multiply elements

8x+2x-2x+4=0

We add all the numbers together, and all the variables

8x+4=0

We move all terms containing x to the left, all other terms to the right

8x=-4

x=-4/8

x=-1/2

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