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4(x-12)+x-3=x-9
We move all terms to the left:
4(x-12)+x-3-(x-9)=0
We add all the numbers together, and all the variables
x+4(x-12)-(x-9)-3=0
We multiply parentheses
x+4x-(x-9)-48-3=0
We get rid of parentheses
x+4x-x+9-48-3=0
We add all the numbers together, and all the variables
4x-42=0
We move all terms containing x to the left, all other terms to the right
4x=42
x=42/4
x=10+1/2
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