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4*2x=7+1/2x
We move all terms to the left:
4*2x-(7+1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4*2x-(1/2x+7)=0
Wy multiply elements
8x-(1/2x+7)=0
We get rid of parentheses
8x-1/2x-7=0
We multiply all the terms by the denominator
8x*2x-7*2x-1=0
Wy multiply elements
16x^2-14x-1=0
a = 16; b = -14; c = -1;
Δ = b2-4ac
Δ = -142-4·16·(-1)
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{65}}{2*16}=\frac{14-2\sqrt{65}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{65}}{2*16}=\frac{14+2\sqrt{65}}{32} $
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