4*sin(2*x)+4*cos(x)+1=0

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Solution for 4*sin(2*x)+4*cos(x)+1=0 equation:


Simplifying
4sin(2x) + 4cos(x) + 1 = 0

Remove parenthesis around (2x)
4ins * 2x + 4cos(x) + 1 = 0

Reorder the terms for easier multiplication:
4 * 2ins * x + 4cos(x) + 1 = 0

Multiply 4 * 2
8ins * x + 4cos(x) + 1 = 0

Multiply ins * x
8insx + 4cos(x) + 1 = 0

Multiply cos * x
8insx + 4cosx + 1 = 0

Reorder the terms:
1 + 4cosx + 8insx = 0

Solving
1 + 4cosx + 8insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 4cosx + -1 + 8insx = 0 + -1

Reorder the terms:
1 + -1 + 4cosx + 8insx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4cosx + 8insx = 0 + -1
4cosx + 8insx = 0 + -1

Combine like terms: 0 + -1 = -1
4cosx + 8insx = -1

Add '-8insx' to each side of the equation.
4cosx + 8insx + -8insx = -1 + -8insx

Combine like terms: 8insx + -8insx = 0
4cosx + 0 = -1 + -8insx
4cosx = -1 + -8insx

Divide each side by '4osx'.
c = -0.25o-1s-1x-1 + -2ino-1

Simplifying
c = -0.25o-1s-1x-1 + -2ino-1

Reorder the terms:
c = -2ino-1 + -0.25o-1s-1x-1

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