4+((1/x)-2)=40

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Solution for 4+((1/x)-2)=40 equation:



4+((1/x)-2)=40
We move all terms to the left:
4+((1/x)-2)-(40)=0
Domain of the equation: x)-2)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
((+1/x)-2)+4-40=0
We add all the numbers together, and all the variables
((+1/x)-2)-36=0
We multiply all the terms by the denominator
((+1-36*x)-2)=0
We calculate terms in parentheses: +((+1-36*x)-2), so:
(+1-36*x)-2
We add all the numbers together, and all the variables
(-36x+1)-2
We get rid of parentheses
-36x+1-2
We add all the numbers together, and all the variables
-36x-1
Back to the equation:
+(-36x-1)
We get rid of parentheses
-36x-1=0
We move all terms containing x to the left, all other terms to the right
-36x=1
x=1/-36
x=-1/36

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