4+((3+12)/y)=9+((3+y)/6)

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Solution for 4+((3+12)/y)=9+((3+y)/6) equation: 



4+((3+12)/y)=9+((3+y)/6)

We move all terms to the left:

4+((3+12)/y)-(9+((3+y)/6))=0



Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(15/y)-(9+((y+3)/6))+4=0

We get rid of parentheses

15/y-(9+((y+3)/6))+4=0

We calculate fractions


()/6y^2+(-(9+((y+3)*y)/6y^2+4=0

We calculate fractions

We do not support eypression: y^4

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