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4+((x+3)/8)=12
We move all terms to the left:
4+((x+3)/8)-(12)=0
We add all the numbers together, and all the variables
((x+3)/8)-8=0
We multiply all the terms by the denominator
((x+3)-8*8)=0
We calculate terms in parentheses: +((x+3)-8*8), so:We get rid of parentheses
(x+3)-8*8
We add all the numbers together, and all the variables
(x+3)-64
We get rid of parentheses
x+3-64
We add all the numbers together, and all the variables
x-61
Back to the equation:
+(x-61)
x-61=0
We move all terms containing x to the left, all other terms to the right
x=61
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