4+((x+3)/8)=12

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Solution for 4+((x+3)/8)=12 equation: 



4+((x+3)/8)=12

We move all terms to the left:

4+((x+3)/8)-(12)=0

We add all the numbers together, and all the variables

((x+3)/8)-8=0

We multiply all the terms by the denominator


((x+3)-8*8)=0



We calculate terms in parentheses: +((x+3)-8*8), so:

(x+3)-8*8

We add all the numbers together, and all the variables

(x+3)-64

We get rid of parentheses

x+3-64

We add all the numbers together, and all the variables

x-61

Back to the equation:

+(x-61)



We get rid of parentheses

x-61=0

We move all terms containing x to the left, all other terms to the right

x=61

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