4+(11/x)+(2/5)=7/2x

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Solution for 4+(11/x)+(2/5)=7/2x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

11/x+2/5+4 = (7/2)*x // - (7/2)*x

11/x-((7/2)*x)+2/5+4 = 0

(-7/2)*x+11/x+2/5+4 = 0

11*x^-1-7/2*x^1+22/5*x^0 = 0

(22/5*x^1-7/2*x^2+11*x^0)/(x^1) = 0 // * x^2

x^1*(22/5*x^1-7/2*x^2+11*x^0) = 0

x^1

(-7/2)*x^2+(22/5)*x+11 = 0

(-7/2)*x^2+(22/5)*x+11 = 0

DELTA = (22/5)^2-(4*11*(-7/2))

DELTA = 4334/25

DELTA > 0

x = ((4334/25)^(1/2)-(22/5))/(2*(-7/2)) or x = (-(22/5)-(4334/25)^(1/2))/(2*(-7/2))

x = ((4334/25)^(1/2)-22/5)/(-7) or x = ((4334/25)^(1/2)+22/5)/7

x in { ((4334/25)^(1/2)-22/5)/(-7), ((4334/25)^(1/2)+22/5)/7} 

x in { ((4334/25)^(1/2)-22/5)/(-7), ((4334/25)^(1/2)+22/5)/7 }

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