4+(2b-5)=13-(3b+7)

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Solution for 4+(2b-5)=13-(3b+7) equation: 



4+(2b-5)=13-(3b+7)

We move all terms to the left:

4+(2b-5)-(13-(3b+7))=0

We get rid of parentheses

2b-(13-(3b+7))-5+4=0



We calculate terms in parentheses: -(13-(3b+7)), so:

13-(3b+7)

determiningTheFunctionDomain
-(3b+7)+13

We get rid of parentheses

-3b-7+13

We add all the numbers together, and all the variables

-3b+6

Back to the equation:

-(-3b+6)



We add all the numbers together, and all the variables

2b-(-3b+6)-1=0

We get rid of parentheses

2b+3b-6-1=0

We add all the numbers together, and all the variables

5b-7=0

We move all terms containing b to the left, all other terms to the right

5b=7

b=7/5

b=1+2/5

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