4+(3-12)=y+27

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Solution for 4+(3-12)=y+27 equation: 



4+(3-12)=y+27

We move all terms to the left:

4+(3-12)-(y+27)=0

We add all the numbers together, and all the variables

-(y+27)+4+(-9)=0

We add all the numbers together, and all the variables

-(y+27)-5=0

We get rid of parentheses

-y-27-5=0

We add all the numbers together, and all the variables

-1y-32=0

We move all terms containing y to the left, all other terms to the right

-y=32

y=32/-1

y=-32

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