4+(3x+2)=6(x+3)+5

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Solution for 4+(3x+2)=6(x+3)+5 equation: 



4+(3x+2)=6(x+3)+5

We move all terms to the left:

4+(3x+2)-(6(x+3)+5)=0

We get rid of parentheses

3x-(6(x+3)+5)+2+4=0



We calculate terms in parentheses: -(6(x+3)+5), so:

6(x+3)+5

We multiply parentheses

6x+18+5

We add all the numbers together, and all the variables

6x+23

Back to the equation:

-(6x+23)



We add all the numbers together, and all the variables

3x-(6x+23)+6=0

We get rid of parentheses

3x-6x-23+6=0

We add all the numbers together, and all the variables

-3x-17=0

We move all terms containing x to the left, all other terms to the right

-3x=17

x=17/-3

x=-5+2/3

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