4+(b+2)=8(b+5)

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Solution for 4+(b+2)=8(b+5) equation: 



4+(b+2)=8(b+5)

We move all terms to the left:

4+(b+2)-(8(b+5))=0

We get rid of parentheses

b-(8(b+5))+2+4=0



We calculate terms in parentheses: -(8(b+5)), so:

8(b+5)

We multiply parentheses

8b+40

Back to the equation:

-(8b+40)



We add all the numbers together, and all the variables

b-(8b+40)+6=0

We get rid of parentheses

b-8b-40+6=0

We add all the numbers together, and all the variables

-7b-34=0

We move all terms containing b to the left, all other terms to the right

-7b=34

b=34/-7

b=-4+6/7

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