4+(x+3y)=(4+x)+3y

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Solution for 4+(x+3y)=(4+x)+3y equation:


Simplifying
4 + (x + 3y) = (4 + x) + 3y

Remove parenthesis around (x + 3y)
4 + x + 3y = (4 + x) + 3y

Remove parenthesis around (4 + x)
4 + x + 3y = 4 + x + 3y

Add '-4' to each side of the equation.
4 + x + -4 + 3y = 4 + x + -4 + 3y

Reorder the terms:
4 + -4 + x + 3y = 4 + x + -4 + 3y

Combine like terms: 4 + -4 = 0
0 + x + 3y = 4 + x + -4 + 3y
x + 3y = 4 + x + -4 + 3y

Reorder the terms:
x + 3y = 4 + -4 + x + 3y

Combine like terms: 4 + -4 = 0
x + 3y = 0 + x + 3y
x + 3y = x + 3y

Add '-1x' to each side of the equation.
x + -1x + 3y = x + -1x + 3y

Combine like terms: x + -1x = 0
0 + 3y = x + -1x + 3y
3y = x + -1x + 3y

Combine like terms: x + -1x = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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