4+(x-5)=3-(3x-2)

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Solution for 4+(x-5)=3-(3x-2) equation: 



4+(x-5)=3-(3x-2)

We move all terms to the left:

4+(x-5)-(3-(3x-2))=0

We get rid of parentheses

x-(3-(3x-2))-5+4=0



We calculate terms in parentheses: -(3-(3x-2)), so:

3-(3x-2)

determiningTheFunctionDomain
-(3x-2)+3

We get rid of parentheses

-3x+2+3

We add all the numbers together, and all the variables

-3x+5

Back to the equation:

-(-3x+5)



We add all the numbers together, and all the variables

x-(-3x+5)-1=0

We get rid of parentheses

x+3x-5-1=0

We add all the numbers together, and all the variables

4x-6=0

We move all terms containing x to the left, all other terms to the right

4x=6

x=6/4

x=1+1/2

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