4+-2+t2=6+t2

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Solution for 4+-2+t2=6+t2 equation: 



4+-2+t2=6+t2

We move all terms to the left:

4+-2+t2-(6+t2)=0

We add all the numbers together, and all the variables

-(+t^2+6)+t2+4-2+=0

We add all the numbers together, and all the variables

t^2-(+t^2+6)=0

We get rid of parentheses

t^2-t^2-6=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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